Y Acos Bx C. Short Answer Period of y = Acos(Bx) +C = (2π/B) Frequency of y = Acos(Bx) +C = (B/2π) Period of y = 1/2 cos x +1 = (2π/1) = 2π Frequency of y = 1/2 cos x +1 = (1/2π) Long Explanatory Answer This is the basic structure of your formula y=Acos(Bx)+C The variable A affects Amplitude The variable B affects Period and the variable C affects Value.

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y = Acos(Bx + c) + D Where A is the amplitude B is called the angular frequency It is the 2pi (period of the cosine function y = cos(x)) divided by T where T is the period of your function T is just the distance of one “cycle” x is your x c is your phase shift for x20180403201307302011061220050106.

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Answer (1 of 2) The key here is to remove the arbitrary constants y = acos(bx+c) > 1 y’ = dy/dx = absin(bx+c) y” = d^2 y/dx^2 = a(b^2)cos(bx+c) > 2 using 1 in 2 we get y” = b^2y or y” + b^2y = 0 =====> ANSWER.

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Thus the absolute value of A is the amplitude of y=Asin(Bx+C)+D When A.

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y = Acos (Bx + C) + D Cosine functions are identical to the sine functions except that they are phaseshifted to the left by 90° By accounting for this shift any sine function can be written as a cosine function and any cosine function can be written as a sine function Example This example will work for both sine and cosine functions.

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The phase shift formula for a trigonometric function such as y = Asin (Bx – C) + D or y = Acos (Bx – C) + D is represented as C / B If C / B is positive the curve moves right and if it is negative the curve moves left Within the general sine function above A represents the amplitude of the wave while B represents the period D is the vertical shift and C is divided by B to find.